Discussion
Predict the output of the following C source code :
int x = 10;
int main( )
{
int x = 20;
{
int x = 30;
{extern x; printf("%d", x);}
}
return 0;
}Answer: A
The program prints 10.
The innermost block declares extern x;, which (with the old implicit int) declares that x refers to an object with external linkage. That is the global int x = 10, not either local x, so within that block printf prints 10.
Without the extern declaration, the innermost local x = 30 would be printed. The value 20 belongs to the outer local that is hidden here, and only one printf runs, so '10 20 30' is impossible.
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