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Two engines each of \( 120 \) kN thrust on an aircraft weighing \( 883 \) kN give a thrust-to-weight ratio of

  • A.0.54
  • B.3.7
  • C.0.27
  • D.0.14

Answer: C

Correct answer: 0.27

Both engines contribute, so

\[ \frac{T}{W} = \frac{2 \times 120}{883} = \frac{240}{883} \approx 0.27 \]

A figure near 0.27 is typical of a twin-engined transport, which must be able to climb away on one engine after failure at the critical point. A fighter runs above 1.0 and can accelerate vertically; the difference in the number expresses the whole difference in mission.

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