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A cone of 60 mm base diameter and 80 mm slant height develops as a sector whose angle is about

  • A.270 degrees
  • B.135 degrees
  • C.60 degrees
  • D.180 degrees

Answer: B

Correct answer: 135 degrees

The sector angle is the base circumference divided by the circumference of a full circle of the slant height: \[ \theta = \frac{r}{L} \times 360 = \frac{30}{80} \times 360 = 135^\circ. \] Note the base radius is used, not the diameter - the 60 mm given is the diameter.

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