Discussion
A cone of 50 mm base radius and 100 mm slant height develops as a sector whose angle is
Answer: C
Correct answer: 180 degrees
\[ \theta = \frac{r}{L} \times 360 = \frac{50}{100} \times 360 = 180^\circ. \] When the slant height is twice the base radius the development is exactly a semicircle, which is a useful case to recognise - it corresponds to a half-angle of 30 degrees at the apex.
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