Machine-translated by Google. Questions are authored in English.
Top

Discussion

The constitutive relation for a linear isotropic dielectric is

  • A.\( \mathbf{D} = \epsilon_r\mathbf{E} \)
  • B.\( \mathbf{E} = \epsilon_0\epsilon_r\mathbf{D} \)
  • C.\( \mathbf{D} = \epsilon_0\epsilon_r\mathbf{E} \)
  • D.\( \mathbf{D} = \epsilon_0\mathbf{E}/\epsilon_r \)

Answer: C

Correct answer: \( \mathbf{D} = \epsilon_0\epsilon_r\mathbf{E} \)

Both factors are needed: \( \epsilon_0 \) carries the units and \( \epsilon_r \) describes the material, so their product is the absolute permittivity. Equivalently \( \mathbf{D} = \epsilon_0\mathbf{E} + \mathbf{P} \), which shows what the relative permittivity is doing - adding the polarisation to the vacuum term. The first option omits \( \epsilon_0 \) and is dimensionally wrong.

No comment is present. Be the first to comment.
Loading…

Post your comment

Please log in or register to post a comment.