Discussion
The energy stored in a capacitor of capacitance \( C \) charged to voltage \( V \) is
Answer: A
The factor of one half arises because the voltage rises from zero to its final value as the charge is delivered, so the mean voltage during charging is half the final one. The same energy may be written as \( Q^2/2C \) or \( \tfrac{1}{2}QV \).
No comment is present. Be the first to comment.
Loading…
Post your comment
Please log in or register to post a comment.
Examination Categories
- SSC Exams
- Banking Exams
- Teaching Exams
- Civil Services Exams
- Railways Exams
- Engineering Recruitment Exams
- Defence Exams
- State Government Exams
- Police Exams
- Insurance Exams
- Nursing Exams
- Other Government Exams
- NRA CET
- PG Entrance Exams
- Campus Placement
- MBA Entrance Exams
- CUET and UG Entrance
- Judiciary Exams
- Regulatory Body Exams
- Software Development