Discussion
A parallel plate capacitor of area 0.01 m² and gap 1 mm in air has a capacitance of about
Answer: A
Correct answer: 88.5 pF
\[ C = \frac{\epsilon_0 A}{d} = \frac{8.854\times10^{-12} \times 0.01}{0.001} = 8.85\times10^{-11}\ \mathrm{F} = 88.5\ \mathrm{pF}. \] The figure is worth remembering as a scale: a hundred square centimetres a millimetre apart gives well under a nanofarad, which is why practical capacitors use very thin dielectrics and very large rolled or stacked areas.
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