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Filling that same capacitor with a dielectric of relative permittivity 4 raises its capacitance to

  • A.1416 pF
  • B.354 pF
  • C.22.1 pF
  • D.88.5 pF

Answer: B

The capacitance is multiplied by the relative permittivity, so \( 4 \times 88.5 = 354 \) pF. The stored energy at a given voltage rises by the same factor, which is why high permittivity ceramics are used where compactness matters.

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