Discussion
The polarisation in a dielectric of relative permittivity 5 in a field of 1000 V/m is about
Answer: D
Correct answer: 35.4 nC/m\( ^2 \)
\[ P = \epsilon_0(\epsilon_r-1)E = 8.854\times10^{-12} \times 4 \times 1000 = 3.54\times10^{-8}\ \mathrm{C/m^2} = 35.4\ \mathrm{nC/m^2}. \] The subtraction of one is what is easily forgotten: using \( \epsilon_r \) itself gives 44.3 nC/m², which is offered here, and would be the flux density rather than the polarisation.
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