Discussion
A capacitor of 1 \( \mu \)F with a leakage resistance of 100 M\( \Omega \) loses its charge with a time constant of
Answer: A
The product is \( 10^{-6} \times 10^{8} = 100 \) seconds, so the voltage falls to about a third in a minute and a half. This is why a large capacitor is fitted with a discharge resistor and why one should never assume a disconnected capacitor is safe to handle.
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