Discussion
The energy stored per unit volume in a dielectric of relative permittivity 4 at a field of 1 MV/m is about
Answer: B
Substituting in \( \tfrac{1}{2}\epsilon_0\epsilon_r E^2 \) gives \( 0.5 \times 8.854 \times 10^{-12} \times 4 \times 10^{12} = 17.7 \) J/m³. Even at a megavolt per metre the density is modest, which is why electrostatic energy storage cannot compete with chemical storage on a volume basis.
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