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For the following OP-amp circuit, R1 = R2 = R3 = RF =1.0 kΩ, the output voltage Vout is :

V1 = +1.0 V, V2 = -5.0 V and V3 = +3.0 V are applied through R1, R2 and R3 to the inverting (-) input; RF connects Vout back to the inverting input; the non-inverting (+) input goes to ground through a resistor

  • A.+1.0V
  • B.-1.0V
  • C.+0.5V
  • D.-0.5V

Answer: A

The output is +1.0V.

The circuit is an inverting summing amplifier. With equal resistors, the output is the negative sum of the inputs:

\[ \begin{aligned} V_{out} &= -R_{F}\left(\frac{V_{1}}{R_{1}} + \frac{V_{2}}{R_{2}} + \frac{V_{3}}{R_{3}}\right) \\ &= -(1.0 - 5.0 + 3.0) = +1.0\ \text{V} \end{aligned} \]

-1.0 V forgets the inversion. The 0.5 V values would follow if \(R_{F}\) were half the input resistors, which it is not.

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