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Taking the output between both collectors instead, that gain becomes about

  • A.100
  • B.400
  • C.50
  • D.200

Answer: D

A double-ended output collects both collectors' opposite excursions:

\[ A_{v(dd)} = 2 \times 100 = 200 \]

giving about 200, twice the single-ended figure, and with the common-mode movement cancelled as well. That one wiring choice buys both twice the gain and better rejection is why a differential output is preferred wherever the following stage can accept one.

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