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Why is a current mirror's output impedance important as an active load?

  • A.It determines the tail current the pair draws
  • B.It fixes the input common-mode range
  • C.It limits the stage's slew rate
  • D.It sets the gain the differential stage reaches

Answer: D

The stage's gain is transconductance times load impedance, so a mirror's hundreds of kilohms let the pair approach its intrinsic gain limit where a practical resistor could not. The tail current, the common-mode range and the slew rate are set elsewhere. That the same component supplies both the conversion to single-ended output and a large increase in gain is why it displaced resistive loading entirely.

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