Discussion
The output waveform for the following OP-Amp configuration is :
- A.
- B.
- C.
- D.
Answer: B
The output is waveform (B), a sine wave swinging between 0 and +2vp.
The circuit is an active positive clamper. The output node is joined to the inverting input, and the capacitor sits between the source and that node. Whenever the node tries to go below 0 V, the op-amp output swings positive, the diode conducts and charges the capacitor, holding the node at 0 V. After the first negative peak the capacitor holds vp, and the diode stays off.
\[ \begin{aligned} v_{out} &= v_{in} + v_{p} \\ 0 &\le v_{out} \le 2v_{p} \end{aligned} \]
Waveform (A) is the input unchanged, (C) is a negative clamper, which needs the diode reversed, and (D) is a clipped shape that no clamper produces.
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