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The value of \( \lim_{x \to 0} x \ln x \) is

  • A.\( 1 \)
  • B.\( -1 \)
  • C.\( 0 \)
  • D.\( -\infty \)

Answer: C

The form is \( 0 \times (-\infty) \), so rewrite it as a quotient and differentiate:

\[ \lim_{x \to 0^{+}} \frac{\ln x}{1/x} \;=\; \lim_{x \to 0^{+}} \frac{1/x}{-1/x^{2}} \;=\; \lim_{x \to 0^{+}} (-x) \;=\; 0. \]

The logarithm diverges, but only as slowly as a logarithm, and the factor \( x \) goes to zero faster than it grows

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