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The \( n \)th derivative of \( e^{ax} \) is

  • A.\( a\,e^{ax} \)
  • B.\( n\,a^{n-1} e^{ax} \)
  • C.\( a^{n} e^{a^{n}x} \)
  • D.\( a^{n} e^{ax} \)

Answer: D

Each differentiation multiplies by the constant \( a \) and leaves the exponential alone, so after \( n \) steps

\[ \frac{d^{n}}{dx^{n}} e^{ax} \;=\; a^{n} e^{ax}. \]

This is why the exponential is the natural basis for linear differential equations: substituting it turns each derivative into a power of \( a \) and the equation into a polynomial

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