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If \( y = \sin x \), then \( y^{(4)} \) equals

  • A.\( -\cos x \)
  • B.\( \sin x \)
  • C.\( -\sin x \)
  • D.\( \cos x \)

Answer: B

The derivatives run in a cycle of four:

\[ \sin x \;\to\; \cos x \;\to\; -\sin x \;\to\; -\cos x \;\to\; \sin x. \]

So the fourth derivative returns the original function, and in general \( y^{(n)} = \sin(x + n\pi/2) \). Any derivative whose order is a multiple of four reproduces the function unchanged

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