Discussion
The curve \( y = \dfrac{2x + 1}{x - 3} \) has asymptotes
Answer: D
The denominator vanishes at \( x = 3 \), giving a vertical asymptote. For the horizontal one, divide through by \( x \):
\[ \lim_{x \to \pm\infty} \frac{2x+1}{x-3} \;=\; \lim_{x \to \pm\infty} \frac{2 + 1/x}{1 - 3/x} \;=\; 2. \]
So \( y = 2 \) is approached at both ends, the ratio of the leading coefficients
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