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The point of inflexion of \( y = x^{3} - 6x^{2} + 9x \) lies at

  • A.\( x = 3 \)
  • B.\( x = 0 \)
  • C.\( x = 2 \)
  • D.\( x = 1 \)

Answer: C

Differentiate twice and set the result to zero:

\[ \frac{dy}{dx} = 3x^{2} - 12x + 9, \qquad \frac{d^{2}y}{dx^{2}} = 6x - 12 \;=\; 0. \]

So \( x = 2 \), and the second derivative changes from negative to positive there, confirming a genuine inflexion. The values \( x = 1 \) and \( x = 3 \) are the stationary points

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