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The reason an integrating digital voltmeter is described as taking a mean rather than a sample is that its converter

  • A.takes many samples and computes their arithmetic average digitally
  • B.compares the input with a reference at a large number of instants
  • C.measures the peak of the input and scales it by a fixed factor
  • D.responds to the area under the input over the measuring period

Answer: D

The integrator's output at the end of the charging phase is proportional to the time integral of the input, which divided by the fixed period is the mean. Nothing is sampled at all, and that is why periodic interference cancels so completely.

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