Machine-translated by Google. Questions are authored in English.
Top

Discussion

The critical inductance in mains power supply ensures that the current through 'L' never becomes zero. For this, critical value of inductance is

  • A.\(\frac{R_L}{310}\)
  • B.\(\frac{R_L}{450}\)
  • C.\(\frac{R_L}{620}\)
  • D.\(\frac{R_L}{942}\)

Answer: D

For a full-wave rectifier with an inductor input filter the critical inductance is \(R_L/3\omega\), which is \(R_L/942\) for a 50 Hz supply (option D).

\[ L_c = \frac{R_L}{3\omega} \]

\[ L_c = \frac{R_L}{3 \times 2\pi \times 50} \]

\[ L_c = \frac{R_L}{942} \]

The other options, \(R_L/310\), \(R_L/450\) and \(R_L/620\), do not come from this relation at 50 Hz; \(R_L/310\) is not a value of \(R_L/3\omega\) for any usual supply frequency.

No comment is present. Be the first to comment.
Loading…

Post your comment

Please log in or register to post a comment.