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A capacitor filter supplies \( 100 \ \mathrm{mA} \) with \( 1000 \ \mathrm{\mu F} \) at \( 100 \ \mathrm{Hz} \) ripple. The peak-to-peak ripple is about

  • A.1 V
  • B.0.1 V
  • C.10 V
  • D.0.5 V

Answer: A

The capacitor discharges at the load current for about one ripple period:

\[ \begin{aligned} \Delta V &= \frac{I t}{C} \\ &= \frac{0.1 \times 0.01}{10^{-3}} = 1 \ \mathrm{V} \end{aligned} \]

giving about 1 volt. The remaining options misplace a decade. The relation says ripple is proportional to load current and inversely to capacitance, which is why a supply's ripple specification is always quoted at a stated load.

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