Discussion
Doubling that capacitor's value changes the ripple to about
Answer: B
Ripple is inversely proportional to capacitance:
\[ \Delta V \propto \frac{1}{C} \]
so doubling the capacitor halves the ripple to about 0.5 volts. Two volts inverts the relationship and a quarter of a volt would need four times the capacitance. Because the improvement is only linear in capacitance, getting ripple down by a large factor with brute capacitance quickly becomes expensive, which is the argument for an active regulator after the filter. Working one numerical case through both schemes side by side fixes the distinction better than any rule of thumb.
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