Discussion
With a heatsink halving that thermal resistance, the same dissipation gives a junction temperature of
Answer: C
Halving the resistance halves the rise:
\[ T_{j} = 40 + (1 \times 30) = 70 \ \mathrm{^\circ C} \]
so 70 degrees, a thirty degree improvement bought entirely with metal. Fifty degrees would need a quarter of the original resistance. Because the rise is proportional to the resistance, halving one halves the other exactly, which makes heatsink sizing one of the more straightforward calculations in a power design.
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