Discussion
For the given clamper circuit, the diode is ideal.
The input Vi is:
The output Vo is:
- A.
- B.
- C.
- D.
Answer: C
The capacitor in series charges through the diode, and the clamper shifts the dc level of the input without changing its shape. The diode is connected with its anode at the output node, so it conducts when the output tries to go positive. During the first half cycle (input \(+V\)) the diode conducts and the capacitor charges to \(V\), keeping the output at about 0 V. When the input falls to \(-V\) the diode is off and the output is the input minus the capacitor voltage, \(-V - V = -2V\).
So the output is a square wave between 0 and \(-2V\), which is figure (C). Figure (A) and (B) swing positive, so they would need the diode reversed, and figure (D) is the input itself without a shift. The answer is option C.
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