Discussion
In the given circuit, the diodes are ideal.
The input to this circuit is:
where \(V_m\) is 250 V. The value of DC output voltage is:
Answer: D
The circuit is a full wave bridge rectifier with ideal diodes. Both half cycles of the input appear at the load with the same polarity, so the average (dc) output voltage is
\[ \begin{aligned} V_{dc} = \frac{2V_m}{\pi} \\ &= \frac{2 \times 250}{\pi} = 159.2\ \text{V} \end{aligned} \]
The value for a half wave rectifier would be \(V_m/\pi = 79.6\) V. The options 0.159, 1.59 and 15.9 V are 1000, 100 and 10 times too small, which would come from \(V_m\) taken as 0.25, 2.5 or 25 V. The answer is 159 V, option D.
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