Discussion
The parallel combination of two diodes are connected in series with battery and resistance as shown in figure. The diodes are identical and have forward breakdown voltage of 0.7 V. The diode currents are __________.
Answer: C
The diode currents are 1.5 mA and 1.5 mA.
The parallel diodes hold 0.7 V across themselves, so the resistor carries the rest of the battery voltage, and the identical diodes share the current equally.
\[ \begin{aligned} I_{1} &= \frac{10 - 0.7}{3.1\ \text{k}\Omega} = 3\ \text{mA} \\ I_{D1} &= I_{D2} = \frac{3}{2} = 1.5\ \text{mA} \end{aligned} \]
3 mA each forgets that the total divides between the two diodes. 3.22 or 3.23 come from ignoring the 0.7 V drop (\(10/3.1 \approx 3.23\) mA), and amperes instead of milliamperes is a units slip.
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