Discussion
In the following Zener regulator circuit, the current through Zener diode Iz is equal to :
Answer: B
The Zener current is 6 mA.
First check that the Zener conducts: without it the load would see \( 30 \times \frac{4}{2 + 4} = 20 \) V, above 12 V, so the Zener is in breakdown and holds the load at 12 V.
\[ \begin{aligned} I &= \frac{30 - 12}{2\ \text{k}\Omega} = 9\ \text{mA} \\ I_{L} &= \frac{12}{4\ \text{k}\Omega} = 3\ \text{mA} \\ I_{z} &= 9 - 3 = 6\ \text{mA} \end{aligned} \]
9 mA would be the answer if the load current were forgotten, and 4, 8 and 10 mA do not satisfy the two current balances above.
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