Discussion
A silicon diode dissipates 5 W of power when the dc current of 2 Amp flows through it. The bulk resistance of the diode is :
Answer: B
The bulk resistance is 0.9 Ω.
The voltage across the diode is \(V = P/I = 5/2 = 2.5\) V. A silicon diode needs about 0.7 V to overcome its barrier potential; the rest drops across its bulk resistance:
\[ r_{B} = \frac{2.5 - 0.7}{2} = \frac{1.8}{2} = 0.9\ \Omega \]
The option 1.2 Ω uses V/I = 2.5/2 without subtracting the barrier potential (and rounds it down), and 2.5 Ω confuses volts with ohms.
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