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Arun and Amit started walking from two different points 'A' and 'B' respectively.Arun walks 2 kms North and turns to the East and walks 3 kms and again turns to North walks 4 kms and finally turns to East and Walks 5kms to reach point 'C'. Similarly, Amit walks 2 kms North and turns to west and walks 3 kms and finally turns to North, walks 4 kms and meets Arun at point 'C'. What is the distance between Arun and Amit's starting points?

  • A.5 km
  • B.8 km
  • C.11 km
  • D.13 km

Answer: C

Correct answer: 11 km

Work backwards from the common point C. Arun’s legs are north 2, east 3, north 4, east 5, so relative to A he has moved 8 east and 6 north, meaning A lies 8 km west and 6 km south of C. Amit’s legs are north 2, west 3, north 4, so relative to B he has moved 3 west and 6 north, meaning B lies 3 km east and 6 km south of C. Both starting points are the same 6 km south of C, so the distance between them is purely east-west: \( 8+3 = 11 \) km.

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