Discussion
City K is 14 km to the west of City J.
City L is 12 km to the south of City N.
City J is 5 km to the east of City L.
City M is 5 km to the north of City L.
City G is 13 km to the west of City M.
Point H is 14 km to the south of Point G.
If Seema is 3 km to the west of City K then how much distance (shortest) does she have to cover to reach City M?
Answer: C
Seema must cover 13 km. Take City L as the origin. J is 5 km east of L, K is 14 km west of J so K is 9 km west of L, and Seema is 3 km west of K, which is 12 km west of L. City M is 5 km north of L. So Seema is 12 km west and M is 5 km north of the same line. The shortest distance is the straight line: the square root of 12 squared plus 5 squared, which is the square root of 169, that is 13 km. The other facts about N, G and H are not needed. 11, 12 and 14 km are not the hypotenuse of a 12 and 5 right triangle.
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