Discussion
The zonal gradient of meridional current and the meridional gradient of zonal current is \(-0.3 \times 10^{-3}\) s-1 and \(0.3 \times 10^{-3}\) s-1, respectively, at a location P (87 °E, 15 °N). Which one of the following best explains the nature of the flow?
Answer: D
The flow is clockwise in nature.
The vertical component of relative vorticity is the zonal gradient of the meridional current minus the meridional gradient of the zonal current:
\[ \begin{aligned} \zeta &= \frac{\partial v}{\partial x} - \frac{\partial u}{\partial y} \\ &= (-0.3 - 0.3) \times 10^{-3} = -0.6 \times 10^{-3}\ \text{s}^{-1} \end{aligned} \]
Negative vorticity means clockwise rotation; at 15 °N this is anticyclonic flow.
The flow is clearly rotational, since \(\zeta \ne 0\). Counter-clockwise rotation would need positive vorticity. Divergence needs the gradients \(\partial u/\partial x\) and \(\partial v/\partial y\), which are not given, so nothing can be said about it from these data.
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