Discussion
A number when divided by 5 leaves a remainder of 3. What is the remainder when the square of the same number is divided by 5?
Answer: D
Write the number as \( 5k + 3 \) and square it.
\[ (5k+3)^{2} = 25k^{2} + 30k + 9 \]
The first two terms are multiples of 5, so only the 9 matters:
\[ 9 = 5 + 4 \quad\Longrightarrow\quad \text{remainder } 4 \]
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