Discussion
What is the remainder when \(143^3\) is divided by 11?
Answer: A
First, let's find the remainder when the base, 143, is divided by 11. Sum of alternate digits: (3+1) - 4 = 0. Since the difference is 0, 143 is divisible by 11. The remainder is 0. Therefore, \(143^3\) will also be divisible by 11, and the remainder will be 0.
No comment is present. Be the first to comment.
Loading…
Post your comment
Please log in or register to post a comment.
Examination Categories
- SSC Exams
- Banking Exams
- Teaching Exams
- Civil Services Exams
- Railways Exams
- Engineering Recruitment Exams
- Defence Exams
- State Government Exams
- Police Exams
- Insurance Exams
- Nursing Exams
- Other Government Exams
- NRA CET
- PG Entrance Exams
- Campus Placement
- MBA Entrance Exams
- CUET and UG Entrance
- Judiciary Exams
- Regulatory Body Exams
- Software Development