Discussion
What is the smallest number that must be added to 1056 to make the sum completely divisible by 23?
Answer: A
First, we divide 1056 by 23 to find the remainder. \(1056 = 45 \times 23 + 21\). The remainder is 21. The number that must be added to make the sum divisible by 23 is \(\text{Divisor} - \text{Remainder} = 23 - 21 = 2\).
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