Discussion

What is the remainder when \(17^{23}\) is divided by 16?

Answer: A

We can express the base 17 as \(16+1\). So, we need to find the remainder of \((16+1)^{23} \div 16\). According to the remainder theorem, this is equivalent to finding the remainder of \(1^{23} \div 16\). Since \(1^{23} = 1\), the remainder is 1.