Discussion
A number is divisible by 13. If we divide that number by 5, it leaves a remainder of 3. What is the smallest such number?
Answer: D
Correct answer: 13
List the multiples of 13 in order and test each against the second condition.
\[13 \div 5 = 2 \text{ remainder } 3\]
The very first multiple already satisfies it, so 13 is the smallest such number. For comparison, 26 leaves remainder 1, 39 leaves 4 and 52 leaves 2, so none of the larger options qualifies as the smallest.
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