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What is the remainder when 86 × 60 × 12 × 60 × 94 is divided by 100?

  • A.6
  • B.1
  • C.2
  • D.0

Answer: D

The remainder is 0.

The remainder on division by 100 is the last two digits of the product. Two of the factors are 60, and \(60 \times 60 = 3600\), which already ends in 00.

Multiplying a number ending in 00 by any whole numbers keeps the last two digits 00, so the whole product \(86 \times 60 \times 12 \times 60 \times 94\) is divisible by 100 and leaves no remainder. Any of the other remainders would need a product not divisible by 100, which the two factors of 60 rule out.

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