Discussion
Klenow fragment without free nucleotides exhibits
Answer: A
Correct answer: exonuclease activity
The Klenow fragment is Pol I with the 5’→3’ exonuclease domain removed, so it retains polymerase and 3’→5’ exonuclease activity. Without free dNTPs it cannot polymerise, so only the exonuclease is left, and it will chew back a 3’ end. This is exactly how Klenow is used to blunt a 3’ overhang.
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