Discussion
Calculate the electrical energy consumed in kWH by an electrical kettle rated at 750 W/250 V used for 90 minutes.
Answer: D
Electrical energy is the power multiplied by the time. The kettle is rated at 750 W and used for 90 minutes, which is 1.5 hours, so the energy is power in kilowatts times time in hours.
\[ E = 0.75\ \mathrm{kW} \times 1.5\ \mathrm{h} \]
\[ E = 1.125\ \mathrm{kWH} \]
So the energy consumed is 1.125 kWH, option (D). The other values do not follow from 750 W and 1.5 hours; 2.22 kWH, 8.1 kWH and 13 kWH are too large for such a kettle.
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