Machine-translated by Google. Questions are authored in English.
Top

Discussion

A message occupies \( 300 \ \mathrm{Hz} \) to \( 3400 \ \mathrm{Hz} \). An SSB signal carrying it occupies

  • A.6200 Hz
  • B.3100 Hz
  • C.6800 Hz
  • D.3400 Hz

Answer: B

Single sideband occupies just the message band:

\[ B = 3400 - 300 = 3100 \ \mathrm{Hz} \]

so 3100 Hz, and the channel spacing on the high-frequency bands is set accordingly. 6800 Hz is the double-sideband figure, twice the highest message frequency. 3400 Hz is the upper message limit rather than the width. And 6200 Hz doubles the message bandwidth, which is the width DSB would occupy if the message truly began at 300 Hz and the sidebands were measured from the carrier.

No comment is present. Be the first to comment.
Loading…

Post your comment

Please log in or register to post a comment.