Machine-translated by Google. Questions are authored in English.
Top

Discussion

A tone of \( 1 \ \mathrm{kHz} \) modulates a \( 100 \ \mathrm{kHz} \) carrier in a balanced modulator. The output contains

  • A.99 and 101 kHz
  • B.100 kHz only
  • C.99, 100 and 101 kHz
  • D.1 and 100 kHz

Answer: A

The balanced modulator cancels the carrier and leaves the sum and difference:

\[ 100 \pm 1 = 99 \ \mathrm{and} \ 101 \ \mathrm{kHz} \]

so 99 and 101 kHz with nothing at 100 kHz. The second option is what a plain amplifier would pass. The third describes full-carrier AM, where the carrier survives. And the last lists the message and carrier frequencies rather than the products, which is the baseband view rather than the passband one.

No comment is present. Be the first to comment.
Loading…

Post your comment

Please log in or register to post a comment.