Discussion
If the dual problem has an unbounded solution, then primal has :
Answer: A
The primal has no feasible solution.
By weak duality, every feasible primal value bounds every feasible dual value: for a max primal, \(c^{T}x \le b^{T}y\). If the primal had even one feasible point, the dual objective would be bounded by its value and could not be unbounded. So an unbounded dual forces an infeasible primal.
The primal cannot then be unbounded or have a feasible solution, which rules out (B) and (C), and 'none of the above' fails because (A) is correct.
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