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Successive peaks in a free vibration record measure 12 mm and 9 mm. The logarithmic decrement is nearest to

  • A.0.750
  • B.0.133
  • C.1.333
  • D.0.288

Answer: D

Taking \( \delta = \ln(12/9) = \ln 1.333 = 0.288 \). Dividing the two amplitudes without taking the logarithm gives 1.333, which is the amplitude ratio itself and not the decrement, and it would imply damping several times larger than the record actually shows.

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