Discussion
A spiral mode has a real root of \( +0.035 \ \mathrm{s^{-1}} \). Against a requirement that the time to double amplitude be at least 20 seconds, the aeroplane is
Answer: C
The doubling time is \( t_2 = \ln 2/\sigma = 0.693/0.035 = 19.8 \ \mathrm{s} \), so the aeroplane sits right on the 20-second requirement and is compliant to the accuracy of the measurement. A divergent spiral is acceptable precisely because it is slow: twenty seconds is many times a pilot's reaction time, and any autopilot holds wings level without effort. The other options come from using the root directly, or from confusing the doubling time with the time constant \( 1/\sigma = 28.6 \) seconds.
No comment is present. Be the first to comment.
Loading…
Post your comment
Please log in or register to post a comment.
Examination Categories
- SSC Exams
- Banking Exams
- Teaching Exams
- Civil Services Exams
- Railways Exams
- Engineering Recruitment Exams
- Defence Exams
- State Government Exams
- Police Exams
- Insurance Exams
- Nursing Exams
- Other Government Exams
- NRA CET
- PG Entrance Exams
- Campus Placement
- MBA Entrance Exams
- CUET and UG Entrance
- Judiciary Exams
- Regulatory Body Exams
- Software Development