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Two aeroplanes have identical short-period frequency and damping, but one has a much larger load factor sensitivity. Compared with the other, that aeroplane will feel

  • A.Crisper, because its control anticipation parameter is higher
  • B.Identical, because frequency and damping are the same
  • C.Unstable, because load factor sensitivity destabilises the mode
  • D.More sluggish, because its control anticipation parameter is lower

Answer: D

The control anticipation parameter is \( \omega_n^{2}/(n/\alpha) \), so a larger load factor sensitivity in the denominator makes it smaller and the aeroplane feel sluggish: a great deal of load factor eventually arrives, but the initial pitch acceleration that would let the pilot anticipate it does not. This is exactly why the parameter was introduced, since frequency and damping alone would have called the two aeroplanes identical. Higher sensitivity cannot raise the parameter, being in the denominator, and it does not affect stability at all.

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