Discussion
The potential 0.5 m from a point charge of 2 nC is about
Answer: C
Correct answer: 36 V
\[ V = \frac{Q}{4\pi\varepsilon_0 r} = \frac{2\times10^{-9}}{4\pi \times 8.854\times10^{-12} \times 0.5} = 36\ \mathrm{V}. \] Note the units: potential is in volts, and an answer quoted in volts per metre has computed the field instead.
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