Discussion
The energy density in a field of 1000 V/m in free space is about
Answer: C
Correct answer: 4.43 \( \mu \)J/m3
\[ u = \tfrac{1}{2}\varepsilon_0 E^2 = 0.5 \times 8.854\times10^{-12} \times 10^6 = 4.43\ \mu\mathrm{J/m^3}. \] Omitting the factor of a half gives 8.85, which is offered here - the half comes from integrating the energy as the field is built up rather than from any property of the medium.
No comment is present. Be the first to comment.
Loading…
Post your comment
Please log in or register to post a comment.
Examination Categories
- SSC Exams
- Banking Exams
- Teaching Exams
- Civil Services Exams
- Railways Exams
- Engineering Recruitment Exams
- Defence Exams
- State Government Exams
- Police Exams
- Insurance Exams
- Nursing Exams
- Other Government Exams
- NRA CET
- PG Entrance Exams
- Campus Placement
- MBA Entrance Exams
- CUET and UG Entrance
- Judiciary Exams
- Regulatory Body Exams
- Software Development