Discussion
The potential difference between radii of 1 mm and 5 mm about a line charge of 1 nC/m is about
Answer: A
Correct answer: 29 V
\[ V = \frac{\lambda}{2\pi\varepsilon_0}\ln\frac{b}{a} = 17.98 \times \ln 5 = 17.98 \times 1.609 = 28.9\ \mathrm{V}. \] The logarithm is the signature of cylindrical geometry: the potential of a line charge has no finite reference at infinity, so only differences between two radii can be quoted.
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